Sitdikov_Ramil vs daaleksandrov
Lichess · blitz · 2025-01-28 · Result 1/2-1/2
White: Sitdikov_Ramil (2283). Black: daaleksandrov (2425).
Opening: Sicilian Defense: Löwenthal Variation
vs
Recorded moves
1. e4 c5 2. Nf3 Nc6 3. d4 cxd4 4. Nxd4 e5 5. Nb5 d6 6. N1c3 a6 7. Na3 b5 8. Nd5 Nge7 9. c4 Nd4 10. Be3 Nxd5 11. exd5 Nf5 12. cxb5 Bd7 13. Be2 Nxe3 14. fxe3 Qh4+ 15. g3 Qe4 16. Kf2 Be7 17. Qd3 Qb4 18. Qb3 Qxb3 19. axb3 axb5 20. Nxb5 O-O 21. Nc7 Rab8 22. Bc4 f5 23. Ra7 Bf6 24. Ne6 Rf7 25. Rha1 Bxe6 26. dxe6 Rxa7 27. Rxa7 Kf8 28. Bd5 Be7 29. Ra8 Rxa8 30. Bxa8 e4 31. Bd5 Bf6 32. b4 Bxb2 33. b5 Bc3 34. b6 Ba5 35. b7 Bc7 36. Ke2 Ke7 37. Kd2 g5 38. Kc3 Bb8 39. Kc4 Kf6 40. Kb5 f4 41. exf4 gxf4 42. gxf4 e3 43. Bf3 Kxe6 44. Kc6 d5 45. Bxd5+ Kf5 46. Bc4 Kxf4 47. Kd7 Kf3 48. h4 h5 49. Ke6 Kg3 50. Be2 Kxh4 51. Kf5 Bc7 52. Ke4 Kg3 53. Bxh5 Kf2 54. Kd5 e2 55. Bxe2 Kxe2 56. Kc6 Bf4 57. b8=Q Bxb8 1/2-1/2
Game PGN
[Event "4 Этап Лиги GARDE Января Team Battle"] [Site "https://lichess.org/3EepaVNl"] [Date "2025.01.28"] [Round "-"] [White "Sitdikov_Ramil"] [Black "daaleksandrov"] [Result "1/2-1/2"] [GameId "3EepaVNl"] [UTCDate "2025.01.28"] [UTCTime "17:40:11"] [WhiteElo "2283"] [BlackElo "2425"] [WhiteRatingDiff "+2"] [BlackRatingDiff "-2"] [BlackTitle "CM"] [BlackFideId "4133650"] [Variant "Standard"] [TimeControl "180+1"] [ECO "B32"] [Opening "Sicilian Defense: Löwenthal Variation"] [Termination "Normal"] 1. e4 c5 2. Nf3 Nc6 3. d4 cxd4 4. Nxd4 e5 5. Nb5 d6 6. N1c3 a6 7. Na3 b5 8. Nd5 Nge7 9. c4 Nd4 10. Be3 Nxd5 11. exd5 Nf5 12. cxb5 Bd7 13. Be2 Nxe3 14. fxe3 Qh4+ 15. g3 Qe4 16. Kf2 Be7 17. Qd3 Qb4 18. Qb3 Qxb3 19. axb3 axb5 20. Nxb5 O-O 21. Nc7 Rab8 22. Bc4 f5 23. Ra7 Bf6 24. Ne6 Rf7 25. Rha1 Bxe6 26. dxe6 Rxa7 27. Rxa7 Kf8 28. Bd5 Be7 29. Ra8 Rxa8 30. Bxa8 e4 31. Bd5 Bf6 32. b4 Bxb2 33. b5 Bc3 34. b6 Ba5 35. b7 Bc7 36. Ke2 Ke7 37. Kd2 g5 38. Kc3 Bb8 39. Kc4 Kf6 40. Kb5 f4 41. exf4 gxf4 42. gxf4 e3 43. Bf3 Kxe6 44. Kc6 d5 45. Bxd5+ Kf5 46. Bc4 Kxf4 47. Kd7 Kf3 48. h4 h5 49. Ke6 Kg3 50. Be2 Kxh4 51. Kf5 Bc7 52. Ke4 Kg3 53. Bxh5 Kf2 54. Kd5 e2 55. Bxe2 Kxe2 56. Kc6 Bf4 57. b8=Q Bxb8 1/2-1/2