osuarts vs arangupta12
Lichess · rapid · 2026-02-24 · Result 0-1
White: osuarts (1722). Black: arangupta12 (1858).
Opening: Petrov's Defense: Three Knights Game
vs
Recorded moves
1. e4 e5 2. Nf3 Nf6 3. Nc3 Bc5 4. Bc4 d6 5. d3 Bg4 6. Bg5 h6 7. Bh4 g5 8. Bg3 Nc6 9. h3 Bh5 10. Bh2 Nd4 11. g4 Nxg4 12. Nxd4 Nf6 13. Nde2 Qd7 14. Bg3 c6 15. Qd2 Bf3 16. Rh2 b5 17. Bb3 a5 18. a3 O-O 19. O-O-O b4 20. Nb1 bxa3 21. Ng1 Bxd1 22. Kxd1 axb2 23. h4 Ng4 24. Rg2 a4 25. Ba2 Nf6 26. hxg5 Qg4+ 27. Qe2 Qxe2+ 28. Nxe2 hxg5 29. Ng1 Kh7 30. Rh2+ Kg6 31. Nf3 Ng4 32. Rg2 f5 33. exf5+ Rxf5 34. Nbd2 a3 35. Ke2 Raf8 36. c4 Bb4 37. Kd1 Rxf3 38. Nxf3 Rxf3 39. Ke2 Rf8 40. Bh2 Nxh2 41. Rxh2 Bc5 42. f3 Rb8 43. Rh1 Kf5 44. Rf1 Kf4 45. Kd2 Bd4 46. Kc2 Rh8 47. Kb3 Bc5 48. Kc2 Rh2+ 49. Kd1 Ke3 50. Ke1 Bb4+ 51. Kd1 Rd2+ 52. Ke1 Kxd3 53. Bb1+ Kxc4 54. Ba2+ Kd4 55. Rf2 Rxf2+ 56. Kxf2 Kc3 57. Ke2 Kc2 58. Ke3 b1=Q 59. Bxb1+ Kxb1 0-1
Game PGN
[Event "rapid 8+0 Team Battle"] [Site "https://lichess.org/FFM6ZSn1"] [Date "2026.02.24"] [Round "-"] [White "osuarts"] [Black "arangupta12"] [Result "0-1"] [GameId "FFM6ZSn1"] [UTCDate "2026.02.24"] [UTCTime "07:23:32"] [WhiteElo "1722"] [BlackElo "1858"] [WhiteRatingDiff "-3"] [BlackRatingDiff "+4"] [BlackBerserk "true"] [Variant "Standard"] [TimeControl "480+0"] [ECO "C42"] [Opening "Petrov's Defense: Three Knights Game"] [Termination "Normal"] 1. e4 e5 2. Nf3 Nf6 3. Nc3 Bc5 4. Bc4 d6 5. d3 Bg4 6. Bg5 h6 7. Bh4 g5 8. Bg3 Nc6 9. h3 Bh5 10. Bh2 Nd4 11. g4 Nxg4 12. Nxd4 Nf6 13. Nde2 Qd7 14. Bg3 c6 15. Qd2 Bf3 16. Rh2 b5 17. Bb3 a5 18. a3 O-O 19. O-O-O b4 20. Nb1 bxa3 21. Ng1 Bxd1 22. Kxd1 axb2 23. h4 Ng4 24. Rg2 a4 25. Ba2 Nf6 26. hxg5 Qg4+ 27. Qe2 Qxe2+ 28. Nxe2 hxg5 29. Ng1 Kh7 30. Rh2+ Kg6 31. Nf3 Ng4 32. Rg2 f5 33. exf5+ Rxf5 34. Nbd2 a3 35. Ke2 Raf8 36. c4 Bb4 37. Kd1 Rxf3 38. Nxf3 Rxf3 39. Ke2 Rf8 40. Bh2 Nxh2 41. Rxh2 Bc5 42. f3 Rb8 43. Rh1 Kf5 44. Rf1 Kf4 45. Kd2 Bd4 46. Kc2 Rh8 47. Kb3 Bc5 48. Kc2 Rh2+ 49. Kd1 Ke3 50. Ke1 Bb4+ 51. Kd1 Rd2+ 52. Ke1 Kxd3 53. Bb1+ Kxc4 54. Ba2+ Kd4 55. Rf2 Rxf2+ 56. Kxf2 Kc3 57. Ke2 Kc2 58. Ke3 b1=Q 59. Bxb1+ Kxb1 0-1