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Fat-Hatter vs Fantazzini

Lichess · blitz · 2022-12-02 · Result 1-0

White: Fat-Hatter (1879). Black: Fantazzini (2006).

Opening: Nimzo-Indian Defense: Sämisch Variation

GAME REPLAY

vs

White’s perspective
FantazziniBlack · Lichess2,006
Fat-HatterWhite · Lichess1,879
Starting position0 / 111
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Recorded moves

1. d4 Nf6 2. c4 e6 3. Nc3 Bb4 4. a3 Bxc3+ 5. bxc3 O-O 6. Nf3 c5 7. e3 b6 8. Be2 Nc6 9. O-O Ba6 10. Rb1 Qe7 11. a4 Na5 12. Nd2 Rfc8 13. Ba3 d6 14. h3 Rc7 15. Bf3 Rd8 16. Be2 cxd4 17. cxd4 Bxc4 18. Bxc4 Nxc4 19. Nxc4 Rxc4 20. Qb3 Rdc8 21. Rfc1 Rxc1+ 22. Rxc1 Rxc1+ 23. Bxc1 Qc7 24. Bd2 h5 25. f3 Nd5 26. Kf2 a6 27. g4 hxg4 28. hxg4 Qc6 29. e4 Nc7 30. d5 exd5 31. exd5 Nxd5 32. a5 b5 33. Be3 Nxe3 34. Qxe3 Qc5 35. Ke2 Qxe3+ 36. Kxe3 Kf8 37. Kd4 Ke7 38. f4 g6 39. Kc3 Ke6 40. Kd4 f6 41. Ke4 f5+ 42. gxf5+ gxf5+ 43. Kd4 Ke7 44. Kd5 Kd7 45. Kd4 Kc6 46. Kc3 Kc5 47. Kd3 Kd5 48. Kc3 Ke4 49. Kb4 Kxf4 50. Kc3 Ke4 51. Kb4 f4 52. Kb3 f3 53. Kc2 f2 54. Kc3 f1=Q 55. Kb4 Qa1 56. Kb3 1-0

Game PGN
[Event "Hourly SuperBlitz Arena"]
[Site "https://lichess.org/LSZQjUEP"]
[Date "2022.12.02"]
[Round "-"]
[White "Fat-Hatter"]
[Black "Fantazzini"]
[Result "1-0"]
[GameId "LSZQjUEP"]
[UTCDate "2022.12.02"]
[UTCTime "08:41:52"]
[WhiteElo "1879"]
[BlackElo "2006"]
[WhiteRatingDiff "+7"]
[BlackRatingDiff "-8"]
[Variant "Standard"]
[TimeControl "180+0"]
[ECO "E24"]
[Opening "Nimzo-Indian Defense: Sämisch Variation"]
[Termination "Time forfeit"]

1. d4 Nf6 2. c4 e6 3. Nc3 Bb4 4. a3 Bxc3+ 5. bxc3 O-O 6. Nf3 c5 7. e3 b6 8. Be2 Nc6 9. O-O Ba6 10. Rb1 Qe7 11. a4 Na5 12. Nd2 Rfc8 13. Ba3 d6 14. h3 Rc7 15. Bf3 Rd8 16. Be2 cxd4 17. cxd4 Bxc4 18. Bxc4 Nxc4 19. Nxc4 Rxc4 20. Qb3 Rdc8 21. Rfc1 Rxc1+ 22. Rxc1 Rxc1+ 23. Bxc1 Qc7 24. Bd2 h5 25. f3 Nd5 26. Kf2 a6 27. g4 hxg4 28. hxg4 Qc6 29. e4 Nc7 30. d5 exd5 31. exd5 Nxd5 32. a5 b5 33. Be3 Nxe3 34. Qxe3 Qc5 35. Ke2 Qxe3+ 36. Kxe3 Kf8 37. Kd4 Ke7 38. f4 g6 39. Kc3 Ke6 40. Kd4 f6 41. Ke4 f5+ 42. gxf5+ gxf5+ 43. Kd4 Ke7 44. Kd5 Kd7 45. Kd4 Kc6 46. Kc3 Kc5 47. Kd3 Kd5 48. Kc3 Ke4 49. Kb4 Kxf4 50. Kc3 Ke4 51. Kb4 f4 52. Kb3 f3 53. Kc2 f2 54. Kc3 f1=Q 55. Kb4 Qa1 56. Kb3 1-0

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