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Kingslayer_87 vs PanosAndrikopoulos

Lichess · rapid · 2022-10-05 · Result 0-1

White: Kingslayer_87 (2063). Black: PanosAndrikopoulos (1929).

Opening: French Defense: Exchange Variation

GAME REPLAY

vs

White’s perspective
PanosAndrikopoulosBlack · Lichess1,929
Kingslayer_87White · Lichess2,063
Starting position0 / 110
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Recorded moves

1. e4 e6 2. d4 d5 3. exd5 Qxd5 4. Nf3 Qd8 5. Nc3 Nf6 6. Bg5 Be7 7. Bd3 O-O 8. O-O Nbd7 9. Qe2 b6 10. Rad1 Bb7 11. Rfe1 Nd5 12. Bxe7 Nxe7 13. Ne5 Nf6 14. Ne4 Nxe4 15. Bxe4 Bxe4 16. Qxe4 Nd5 17. c4 Nf6 18. Qh4 Qd6 19. Re3 Nd7 20. Rh3 h6 21. Ng4 e5 22. Rg3 Kh7 23. Ne3 f5 24. Qh5 f4 25. Nf5 fxg3 26. Nxd6 gxf2+ 27. Kf1 cxd6 28. dxe5 Nxe5 29. Rxd6 Nxc4 30. Qg6+ Kh8 31. Rd3 Rae8 32. Rf3 Nd2+ 33. Kxf2 Nxf3 34. gxf3 Re7 35. Qd6 Ref7 36. Qd3 Rxf3+ 37. Qxf3 Rxf3+ 38. Kxf3 Kh7 39. h4 g5 40. hxg5 hxg5 41. Kg4 Kg6 42. a4 Kf6 43. b4 Ke5 44. Kxg5 Kd5 45. Kf4 Kc4 46. a5 Kxb4 47. axb6 axb6 48. Ke3 Kc3 49. Ke2 b5 50. Kd1 Kb2 51. Kd2 b4 52. Kd3 b3 53. Kc4 Kc2 54. Kb4 b2 55. Kc4 b1=Q 0-1

Game PGN
[Event "rated rapid game"]
[Site "https://lichess.org/P7UCMLtz"]
[Date "2022.10.05"]
[Round "-"]
[White "Kingslayer_87"]
[Black "PanosAndrikopoulos"]
[Result "0-1"]
[GameId "P7UCMLtz"]
[UTCDate "2022.10.05"]
[UTCTime "14:43:56"]
[WhiteElo "2063"]
[BlackElo "1929"]
[WhiteRatingDiff "-8"]
[BlackRatingDiff "+8"]
[Variant "Standard"]
[TimeControl "600+0"]
[ECO "C01"]
[Opening "French Defense: Exchange Variation"]
[Termination "Normal"]

1. e4 e6 2. d4 d5 3. exd5 Qxd5 4. Nf3 Qd8 5. Nc3 Nf6 6. Bg5 Be7 7. Bd3 O-O 8. O-O Nbd7 9. Qe2 b6 10. Rad1 Bb7 11. Rfe1 Nd5 12. Bxe7 Nxe7 13. Ne5 Nf6 14. Ne4 Nxe4 15. Bxe4 Bxe4 16. Qxe4 Nd5 17. c4 Nf6 18. Qh4 Qd6 19. Re3 Nd7 20. Rh3 h6 21. Ng4 e5 22. Rg3 Kh7 23. Ne3 f5 24. Qh5 f4 25. Nf5 fxg3 26. Nxd6 gxf2+ 27. Kf1 cxd6 28. dxe5 Nxe5 29. Rxd6 Nxc4 30. Qg6+ Kh8 31. Rd3 Rae8 32. Rf3 Nd2+ 33. Kxf2 Nxf3 34. gxf3 Re7 35. Qd6 Ref7 36. Qd3 Rxf3+ 37. Qxf3 Rxf3+ 38. Kxf3 Kh7 39. h4 g5 40. hxg5 hxg5 41. Kg4 Kg6 42. a4 Kf6 43. b4 Ke5 44. Kxg5 Kd5 45. Kf4 Kc4 46. a5 Kxb4 47. axb6 axb6 48. Ke3 Kc3 49. Ke2 b5 50. Kd1 Kb2 51. Kd2 b4 52. Kd3 b3 53. Kc4 Kc2 54. Kb4 b2 55. Kc4 b1=Q 0-1

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