EmanuelPau vs Celevra82
Lichess · blitz · 2022-07-03 · Result 1/2-1/2
White: EmanuelPau (1848). Black: Celevra82 (2227).
Opening: Queen's Pawn Game: London System, with e6
vs
Recorded moves
1. d4 e6 2. Bf4 d5 3. Nf3 Bd6 4. Bxd6 cxd6 5. e3 Nf6 6. c3 O-O 7. Nbd2 Nc6 8. Bd3 b6 9. Bc2 Bb7 10. Nb3 e5 11. dxe5 dxe5 12. e4 dxe4 13. Qxd8 Rfxd8 14. Ng5 Ne7 15. O-O h6 16. Nh3 Rac8 17. Rfe1 a5 18. a4 Bd5 19. Rad1 Be6 20. Rxd8+ Rxd8 21. f4 exf3 22. Nf2 fxg2 23. Be4 Bxb3 24. Bxg2 Rd2 25. Rxe5 Ng6 26. Re3 Rxb2 27. Rd3 Bxa4 28. Rd8+ Kh7 29. Ne4 Rxg2+ 30. Kxg2 Nxe4 31. Rd4 Nxc3 32. Rc4 b5 33. Rxc3 b4 34. Rc4 Bb3 35. Rc1 Nf4+ 36. Kf3 Nd3 37. Rb1 a4 38. Ke3 Nc5 39. Kd4 Ne6+ 40. Kd3 f5 41. Rf1 a3 42. Rxf5 a2 43. Rf1 Nc5+ 44. Kd4 Na4 45. Kd3 Nc3 46. Kd2 Nb1+ 47. Rxb1 axb1=Q 48. Ke3 Qh1 49. Kd4 Qxh2 50. Kc5 Qh5+ 51. Kxb4 Qd5 52. Kc3 Ba4 53. Kb4 g5 54. Kxa4 g4 55. Kb4 g3 56. Kc3 g2 57. Kb4 g1=Q 58. Kc3 1/2-1/2
Game PGN
[Event "Lichess Liga 5C Team Battle"] [Site "https://lichess.org/TnqE8avx"] [Date "2022.07.03"] [Round "-"] [White "EmanuelPau"] [Black "Celevra82"] [Result "1/2-1/2"] [GameId "TnqE8avx"] [UTCDate "2022.07.03"] [UTCTime "18:38:00"] [WhiteElo "1848"] [BlackElo "2227"] [WhiteRatingDiff "+4"] [BlackRatingDiff "-4"] [BlackBerserk "true"] [Variant "Standard"] [TimeControl "180+0"] [ECO "D02"] [Opening "Queen's Pawn Game: London System, with e6"] [Termination "Time forfeit"] 1. d4 e6 2. Bf4 d5 3. Nf3 Bd6 4. Bxd6 cxd6 5. e3 Nf6 6. c3 O-O 7. Nbd2 Nc6 8. Bd3 b6 9. Bc2 Bb7 10. Nb3 e5 11. dxe5 dxe5 12. e4 dxe4 13. Qxd8 Rfxd8 14. Ng5 Ne7 15. O-O h6 16. Nh3 Rac8 17. Rfe1 a5 18. a4 Bd5 19. Rad1 Be6 20. Rxd8+ Rxd8 21. f4 exf3 22. Nf2 fxg2 23. Be4 Bxb3 24. Bxg2 Rd2 25. Rxe5 Ng6 26. Re3 Rxb2 27. Rd3 Bxa4 28. Rd8+ Kh7 29. Ne4 Rxg2+ 30. Kxg2 Nxe4 31. Rd4 Nxc3 32. Rc4 b5 33. Rxc3 b4 34. Rc4 Bb3 35. Rc1 Nf4+ 36. Kf3 Nd3 37. Rb1 a4 38. Ke3 Nc5 39. Kd4 Ne6+ 40. Kd3 f5 41. Rf1 a3 42. Rxf5 a2 43. Rf1 Nc5+ 44. Kd4 Na4 45. Kd3 Nc3 46. Kd2 Nb1+ 47. Rxb1 axb1=Q 48. Ke3 Qh1 49. Kd4 Qxh2 50. Kc5 Qh5+ 51. Kxb4 Qd5 52. Kc3 Ba4 53. Kb4 g5 54. Kxa4 g4 55. Kb4 g3 56. Kc3 g2 57. Kb4 g1=Q 58. Kc3 1/2-1/2