podia vs ArmMorphy41
Lichess · classical · 2023-04-28 · Result 0-1
White: podia (1710). Black: ArmMorphy41 (1979).
Opening: Sicilian Defense: Delayed Alapin Variation, with e6
vs
Recorded moves
1. e4 c5 2. Nf3 e6 3. c3 d5 4. exd5 Qxd5 5. d4 Nc6 6. Bb5 a6 7. Bxc6+ bxc6 8. O-O Nf6 9. dxc5 Qxd1 10. Rxd1 Bxc5 11. Bg5 h6 12. Bxf6 gxf6 13. Nbd2 Bb6 14. Ne4 Ke7 15. Rd3 Rd8 16. Rxd8 Kxd8 17. Rd1+ Ke7 18. Nh4 Bc7 19. f3 Bb7 20. Nc5 Bb6 21. Rd7+ Kf8 22. b4 Rb8 23. Kf1 Bxc5 24. bxc5 Ke8 25. Rd4 a5 26. Ke2 Ba6+ 27. Ke3 Rb2 28. a4 Re2+ 29. Kf4 e5+ 30. Kf5 exd4 31. cxd4 Ke7 32. h3 Bd3+ 33. Kf4 Ra2 34. g4 Rxa4 35. Ke3 Bf1 36. Nf5+ Kf8 37. Nxh6 Bxh3 38. Nf5 Ra3+ 39. Kf4 Bg2 40. Nh4 Bh1 41. g5 fxg5+ 42. Kxg5 Rxf3 43. Nxf3 Bxf3 44. Kf4 Bd5 45. Ke3 a4 46. Kd2 a3 47. Kc2 a2 48. Kb2 Ke7 49. Ka1 Kf6 50. Kb2 Kf5 51. Ka1 Ke4 52. Kb2 Kxd4 53. Ka1 Kxc5 54. Kb2 f5 55. Ka1 f4 56. Kb2 f3 57. Ka1 f2 58. Kb2 f1=Q 0-1
Game PGN
[Event "Monthly Classical Arena"] [Site "https://lichess.org/TuqeRAa6"] [Date "2023.04.28"] [Round "-"] [White "podia"] [Black "ArmMorphy41"] [Result "0-1"] [GameId "TuqeRAa6"] [UTCDate "2023.04.28"] [UTCTime "18:55:57"] [WhiteElo "1710"] [BlackElo "1979"] [WhiteRatingDiff "-6"] [BlackRatingDiff "+2"] [WhiteBerserk "true"] [BlackBerserk "true"] [Variant "Standard"] [TimeControl "1200+10"] [ECO "B40"] [Opening "Sicilian Defense: Delayed Alapin Variation, with e6"] [Termination "Normal"] 1. e4 c5 2. Nf3 e6 3. c3 d5 4. exd5 Qxd5 5. d4 Nc6 6. Bb5 a6 7. Bxc6+ bxc6 8. O-O Nf6 9. dxc5 Qxd1 10. Rxd1 Bxc5 11. Bg5 h6 12. Bxf6 gxf6 13. Nbd2 Bb6 14. Ne4 Ke7 15. Rd3 Rd8 16. Rxd8 Kxd8 17. Rd1+ Ke7 18. Nh4 Bc7 19. f3 Bb7 20. Nc5 Bb6 21. Rd7+ Kf8 22. b4 Rb8 23. Kf1 Bxc5 24. bxc5 Ke8 25. Rd4 a5 26. Ke2 Ba6+ 27. Ke3 Rb2 28. a4 Re2+ 29. Kf4 e5+ 30. Kf5 exd4 31. cxd4 Ke7 32. h3 Bd3+ 33. Kf4 Ra2 34. g4 Rxa4 35. Ke3 Bf1 36. Nf5+ Kf8 37. Nxh6 Bxh3 38. Nf5 Ra3+ 39. Kf4 Bg2 40. Nh4 Bh1 41. g5 fxg5+ 42. Kxg5 Rxf3 43. Nxf3 Bxf3 44. Kf4 Bd5 45. Ke3 a4 46. Kd2 a3 47. Kc2 a2 48. Kb2 Ke7 49. Ka1 Kf6 50. Kb2 Kf5 51. Ka1 Ke4 52. Kb2 Kxd4 53. Ka1 Kxc5 54. Kb2 f5 55. Ka1 f4 56. Kb2 f3 57. Ka1 f2 58. Kb2 f1=Q 0-1