Choytea vs daaleksandrov
Lichess · blitz · 2023-02-09 · Result 0-1
White: Choytea (1895). Black: daaleksandrov (2366).
Opening: Italian Game: Two Knights Defense, Modern Bishop's Opening
vs
Recorded moves
1. e4 e5 2. Nf3 Nc6 3. Bc4 Nf6 4. d3 Be7 5. O-O O-O 6. Be3 d5 7. exd5 Nxd5 8. Nbd2 Be6 9. Bxd5 Bxd5 10. c4 Be6 11. Ne4 b6 12. a3 h6 13. b4 f5 14. Nc3 Bf6 15. Qc2 Qd7 16. Rad1 Rad8 17. d4 exd4 18. b5 Qf7 19. bxc6 dxc3 20. Rxd8 Rxd8 21. Rd1 Rxd1+ 22. Qxd1 Bxc4 23. Bd4 Qd5 24. h3 c2 25. Qd2 Bxd4 26. Nxd4 Qxd4 27. Qxd4 c1=Q+ 28. Kh2 Bf7 29. Qd8+ Kh7 30. Qxc7 Bd5 31. Qe5 Qxc6 32. Qxf5+ Kg8 33. f3 Qd6+ 34. Kh1 Qe6 35. Qc2 a5 36. Qc7 Kh7 37. Qc2+ Qg6 38. Qc7 Qc6 39. Qf4 b5 40. Qf5+ Kg8 41. Qe5 Bf7 42. Qb8+ Kh7 43. Qf4 Bg6 44. h4 Qc4 45. Qg3 Qc1+ 46. Kh2 Qxa3 47. Qe5 Qd3 48. h5 Bf5 49. g4 Bd7 50. Kg3 Bc6 51. Qf4 Qxf3+ 52. Qxf3 Bxf3 53. Kxf3 a4 54. Ke3 a3 55. Kd3 a2 56. Kc3 a1=Q+ 0-1
Game PGN
[Event "Шахматы для Каждого"] [Site "https://lichess.org/Vez64b07"] [Date "2023.02.09"] [Round "-"] [White "Choytea"] [Black "daaleksandrov"] [Result "0-1"] [GameId "Vez64b07"] [UTCDate "2023.02.09"] [UTCTime "18:16:37"] [WhiteElo "1895"] [BlackElo "2366"] [WhiteRatingDiff "+0"] [BlackRatingDiff "+1"] [BlackTitle "CM"] [BlackFideId "4133650"] [Variant "Standard"] [TimeControl "300+3"] [ECO "C55"] [Opening "Italian Game: Two Knights Defense, Modern Bishop's Opening"] [Termination "Normal"] 1. e4 e5 2. Nf3 Nc6 3. Bc4 Nf6 4. d3 Be7 5. O-O O-O 6. Be3 d5 7. exd5 Nxd5 8. Nbd2 Be6 9. Bxd5 Bxd5 10. c4 Be6 11. Ne4 b6 12. a3 h6 13. b4 f5 14. Nc3 Bf6 15. Qc2 Qd7 16. Rad1 Rad8 17. d4 exd4 18. b5 Qf7 19. bxc6 dxc3 20. Rxd8 Rxd8 21. Rd1 Rxd1+ 22. Qxd1 Bxc4 23. Bd4 Qd5 24. h3 c2 25. Qd2 Bxd4 26. Nxd4 Qxd4 27. Qxd4 c1=Q+ 28. Kh2 Bf7 29. Qd8+ Kh7 30. Qxc7 Bd5 31. Qe5 Qxc6 32. Qxf5+ Kg8 33. f3 Qd6+ 34. Kh1 Qe6 35. Qc2 a5 36. Qc7 Kh7 37. Qc2+ Qg6 38. Qc7 Qc6 39. Qf4 b5 40. Qf5+ Kg8 41. Qe5 Bf7 42. Qb8+ Kh7 43. Qf4 Bg6 44. h4 Qc4 45. Qg3 Qc1+ 46. Kh2 Qxa3 47. Qe5 Qd3 48. h5 Bf5 49. g4 Bd7 50. Kg3 Bc6 51. Qf4 Qxf3+ 52. Qxf3 Bxf3 53. Kxf3 a4 54. Ke3 a3 55. Kd3 a2 56. Kc3 a1=Q+ 0-1