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PakUjangKecot vs Hendamsport

Lichess · blitz · 2025-02-15 · Result 1-0

White: PakUjangKecot (1971). Black: Hendamsport (2100).

Opening: Four Knights Game: Scotch Variation Accepted

GAME REPLAY

vs

White’s perspective
HendamsportBlack · Lichess2,100
PakUjangKecotWhite · Lichess1,971
Starting position0 / 107
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Recorded moves

1. e4 e5 2. Nf3 Nc6 3. Nc3 Nf6 4. d4 exd4 5. Nxd4 Bb4 6. Nxc6 bxc6 7. Qd4 Qe7 8. f3 d5 9. e5 Nd7 10. f4 Bb7 11. Bd2 c5 12. Qd3 d4 13. Ne2 Bxd2+ 14. Qxd2 g5 15. O-O-O gxf4 16. Nxf4 O-O-O 17. Bb5 Nxe5 18. Rhe1 f6 19. Nd3 Qd6 20. Nxe5 fxe5 21. Kb1 e4 22. Qa5 a6 23. Bc4 Rhe8 24. a3 e3 25. g3 Kb8 26. Rd3 Qb6 27. Qa4 Ka7 28. Rb3 Qc6 29. Bb5 Qe6 30. Bxe8 Rxe8 31. Ka1 Bd5 32. Rd3 Bc4 33. Rdd1 Bb5 34. Qa5 Re7 35. a4 e2 36. Rd2 Qb6 37. Qxb6+ Kxb6 38. axb5 axb5 39. Rdxe2 Rxe2 40. Rxe2 c4 41. Re7 c5 42. Rxh7 Kc6 43. Kb1 Kd5 44. Kc1 b4 45. Kd2 c3+ 46. bxc3 dxc3+ 47. Kd3 c4+ 48. Ke3 b3 49. cxb3 cxb3 50. Kd3 c2 51. Rc7 Kd6 52. Rc3 Kd5 53. Rxb3 c1=Q 54. Rb5+ 1-0

Game PGN
[Event "Winter champions 9 Team Battle"]
[Site "https://lichess.org/VumNKMHF"]
[Date "2025.02.15"]
[Round "-"]
[White "PakUjangKecot"]
[Black "Hendamsport"]
[Result "1-0"]
[GameId "VumNKMHF"]
[UTCDate "2025.02.15"]
[UTCTime "11:36:26"]
[WhiteElo "1971"]
[BlackElo "2100"]
[WhiteRatingDiff "+7"]
[BlackRatingDiff "-8"]
[Variant "Standard"]
[TimeControl "180+0"]
[ECO "C47"]
[Opening "Four Knights Game: Scotch Variation Accepted"]
[Termination "Time forfeit"]

1. e4 e5 2. Nf3 Nc6 3. Nc3 Nf6 4. d4 exd4 5. Nxd4 Bb4 6. Nxc6 bxc6 7. Qd4 Qe7 8. f3 d5 9. e5 Nd7 10. f4 Bb7 11. Bd2 c5 12. Qd3 d4 13. Ne2 Bxd2+ 14. Qxd2 g5 15. O-O-O gxf4 16. Nxf4 O-O-O 17. Bb5 Nxe5 18. Rhe1 f6 19. Nd3 Qd6 20. Nxe5 fxe5 21. Kb1 e4 22. Qa5 a6 23. Bc4 Rhe8 24. a3 e3 25. g3 Kb8 26. Rd3 Qb6 27. Qa4 Ka7 28. Rb3 Qc6 29. Bb5 Qe6 30. Bxe8 Rxe8 31. Ka1 Bd5 32. Rd3 Bc4 33. Rdd1 Bb5 34. Qa5 Re7 35. a4 e2 36. Rd2 Qb6 37. Qxb6+ Kxb6 38. axb5 axb5 39. Rdxe2 Rxe2 40. Rxe2 c4 41. Re7 c5 42. Rxh7 Kc6 43. Kb1 Kd5 44. Kc1 b4 45. Kd2 c3+ 46. bxc3 dxc3+ 47. Kd3 c4+ 48. Ke3 b3 49. cxb3 cxb3 50. Kd3 c2 51. Rc7 Kd6 52. Rc3 Kd5 53. Rxb3 c1=Q 54. Rb5+ 1-0

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