SOTIRIS2 vs sato4444
Lichess · bullet · 2025-08-02 · Result 1/2-1/2
White: SOTIRIS2 (2651). Black: sato4444 (2587).
Opening: Hungarian Opening: Indian Defense
vs
Recorded moves
1. g3 Nf6 2. Bg2 d5 3. e3 e5 4. Ne2 Bd6 5. O-O h5 6. d4 h4 7. dxe5 Bxe5 8. Nf4 c6 9. c4 Bg4 10. Bf3 Bxf3 11. Qxf3 hxg3 12. fxg3 Bxf4 13. exf4 dxc4 14. Nc3 O-O 15. Be3 Nd5 16. Rad1 Re8 17. Nxd5 cxd5 18. Rxd5 Qe7 19. Re5 Qd7 20. Rd1 Qc8 21. Qe4 Nc6 22. Rxe8+ Qxe8 23. Qf3 Qe6 24. Re1 Re8 25. Bf2 Qd7 26. Rd1 Qe6 27. Kg2 g6 28. g4 Qe4 29. Kg3 Qxf3+ 30. Kxf3 Rd8 31. b3 Rxd1 32. bxc4 Ra1 33. Bxa7 Rxa2 34. Bc5 Rc2 35. f5 Rxc4 36. Bg1 gxf5 37. gxf5 Kg7 38. h4 Kf6 39. h5 Kxf5 40. h6 Kg6 41. h7 Kxh7 42. Bb6 Rb4 43. Bc7 b5 44. Bd6 Rd4 45. Bc5 Rc4 46. Bf8 Kg8 47. Bd6 b4 48. Ke3 b3 49. Kd3 Rc2 50. Ba3 Kg7 51. Ke3 Kf6 52. Kd3 Ke6 53. Ke3 f5 54. Kd3 f4 55. Bb2 Kd5 56. Bc3 Rxc3+ 57. Kxc3 f3 58. Kb2 f2 59. Kxb3 f1=Q 60. Kc2 Qf3 61. Kd2 1/2-1/2
Game PGN
[Event "2025 Summer Marathon"] [Site "https://lichess.org/j2DhKpj7"] [Date "2025.08.02"] [Round "-"] [White "SOTIRIS2"] [Black "sato4444"] [Result "1/2-1/2"] [GameId "j2DhKpj7"] [UTCDate "2025.08.02"] [UTCTime "11:29:21"] [WhiteElo "2651"] [BlackElo "2587"] [WhiteRatingDiff "-1"] [BlackRatingDiff "+1"] [Variant "Standard"] [TimeControl "60+0"] [ECO "A00"] [Opening "Hungarian Opening: Indian Defense"] [Termination "Time forfeit"] 1. g3 Nf6 2. Bg2 d5 3. e3 e5 4. Ne2 Bd6 5. O-O h5 6. d4 h4 7. dxe5 Bxe5 8. Nf4 c6 9. c4 Bg4 10. Bf3 Bxf3 11. Qxf3 hxg3 12. fxg3 Bxf4 13. exf4 dxc4 14. Nc3 O-O 15. Be3 Nd5 16. Rad1 Re8 17. Nxd5 cxd5 18. Rxd5 Qe7 19. Re5 Qd7 20. Rd1 Qc8 21. Qe4 Nc6 22. Rxe8+ Qxe8 23. Qf3 Qe6 24. Re1 Re8 25. Bf2 Qd7 26. Rd1 Qe6 27. Kg2 g6 28. g4 Qe4 29. Kg3 Qxf3+ 30. Kxf3 Rd8 31. b3 Rxd1 32. bxc4 Ra1 33. Bxa7 Rxa2 34. Bc5 Rc2 35. f5 Rxc4 36. Bg1 gxf5 37. gxf5 Kg7 38. h4 Kf6 39. h5 Kxf5 40. h6 Kg6 41. h7 Kxh7 42. Bb6 Rb4 43. Bc7 b5 44. Bd6 Rd4 45. Bc5 Rc4 46. Bf8 Kg8 47. Bd6 b4 48. Ke3 b3 49. Kd3 Rc2 50. Ba3 Kg7 51. Ke3 Kf6 52. Kd3 Ke6 53. Ke3 f5 54. Kd3 f4 55. Bb2 Kd5 56. Bc3 Rxc3+ 57. Kxc3 f3 58. Kb2 f2 59. Kxb3 f1=Q 60. Kc2 Qf3 61. Kd2 1/2-1/2