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khinela vs ambaras

Lichess · blitz · 2022-11-18 · Result 0-1

White: khinela (2021). Black: ambaras (2089).

Opening: Slav Defense: Three Knights Variation

GAME REPLAY

vs

White’s perspective
ambarasBlack · Lichess2,089
khinelaWhite · Lichess2,021
Starting position0 / 110
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Recorded moves

1. d4 d5 2. c4 c6 3. Nf3 Nf6 4. Nc3 Bg4 5. e3 e6 6. h3 Bxf3 7. Qxf3 Be7 8. Bd2 Nbd7 9. Be2 O-O 10. O-O dxc4 11. a4 Nb6 12. a5 Nbd5 13. Bxc4 Nxc3 14. Bxc3 Nd5 15. e4 Nxc3 16. bxc3 c5 17. Rfd1 cxd4 18. cxd4 Rc8 19. Be2 Bb4 20. a6 b6 21. d5 e5 22. Rac1 Bc5 23. Bb5 Qd6 24. Bc6 Rc7 25. Bb7 g6 26. g4 Kg7 27. Kh1 f6 28. Rg1 Rff7 29. Qe2 Rxb7 30. axb7 Rxb7 31. Qa6 Qd7 32. Ra1 Bxf2 33. Rgf1 Bd4 34. Rac1 Bc5 35. g5 fxg5 36. Rf3 Rc7 37. Rcf1 Kh6 38. Qe2 a5 39. Qe1 a4 40. h4 Be7 41. Rf7 Qh3+ 42. Kg1 Bc5+ 43. R1f2 Rxf7 44. hxg5+ Kg7 45. d6 Bxf2+ 46. Qxf2 Rxf2 47. Kxf2 Qd3 48. d7 Qxd7 49. Kf3 a3 50. Ke3 a2 51. Kf3 Qd3+ 52. Kg4 Qxe4+ 53. Kg3 a1=Q 54. Kh3 Qc3+ 55. Kh2 Qec2+ 0-1

Game PGN
[Event "48th Lichess Mega A Team Battle"]
[Site "https://lichess.org/nyPUG7GT"]
[Date "2022.11.18"]
[Round "-"]
[White "khinela"]
[Black "ambaras"]
[Result "0-1"]
[GameId "nyPUG7GT"]
[UTCDate "2022.11.18"]
[UTCTime "18:47:48"]
[WhiteElo "2021"]
[BlackElo "2089"]
[WhiteRatingDiff "-5"]
[BlackRatingDiff "+5"]
[Variant "Standard"]
[TimeControl "180+2"]
[ECO "D15"]
[Opening "Slav Defense: Three Knights Variation"]
[Termination "Normal"]

1. d4 d5 2. c4 c6 3. Nf3 Nf6 4. Nc3 Bg4 5. e3 e6 6. h3 Bxf3 7. Qxf3 Be7 8. Bd2 Nbd7 9. Be2 O-O 10. O-O dxc4 11. a4 Nb6 12. a5 Nbd5 13. Bxc4 Nxc3 14. Bxc3 Nd5 15. e4 Nxc3 16. bxc3 c5 17. Rfd1 cxd4 18. cxd4 Rc8 19. Be2 Bb4 20. a6 b6 21. d5 e5 22. Rac1 Bc5 23. Bb5 Qd6 24. Bc6 Rc7 25. Bb7 g6 26. g4 Kg7 27. Kh1 f6 28. Rg1 Rff7 29. Qe2 Rxb7 30. axb7 Rxb7 31. Qa6 Qd7 32. Ra1 Bxf2 33. Rgf1 Bd4 34. Rac1 Bc5 35. g5 fxg5 36. Rf3 Rc7 37. Rcf1 Kh6 38. Qe2 a5 39. Qe1 a4 40. h4 Be7 41. Rf7 Qh3+ 42. Kg1 Bc5+ 43. R1f2 Rxf7 44. hxg5+ Kg7 45. d6 Bxf2+ 46. Qxf2 Rxf2 47. Kxf2 Qd3 48. d7 Qxd7 49. Kf3 a3 50. Ke3 a2 51. Kf3 Qd3+ 52. Kg4 Qxe4+ 53. Kg3 a1=Q 54. Kh3 Qc3+ 55. Kh2 Qec2+ 0-1

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