anubabbu vs Maxanam
Lichess · rapid · 2025-01-05 · Result 1/2-1/2
White: anubabbu (1783). Black: Maxanam (1805).
Opening: French Defense: Classical Variation, Steinitz Variation
vs
Recorded moves
1. d4 d5 2. e4 e6 3. Nc3 Nf6 4. e5 Nfd7 5. Be3 c5 6. Nce2 cxd4 7. Qxd4 Nc6 8. Qg4 Ndxe5 9. Qg3 g6 10. Nf3 Bg7 11. Ned4 Nxf3+ 12. Nxf3 Bxb2 13. Rb1 Bc3+ 14. Bd2 Bxd2+ 15. Nxd2 Qf6 16. Bb5 Bd7 17. Qd6 Qe5+ 18. Qxe5 Nxe5 19. Bxd7+ Kxd7 20. Rxb7+ Kc6 21. Rb1 Rab8 22. Ke2 Rxb1 23. Rxb1 Ng4 24. h3 Ne5 25. a4 Rc8 26. f4 Nd7 27. Kd3 Nc5+ 28. Kd4 Nxa4 29. Rb4 Nc5 30. Ke5 Nd7+ 31. Kd4 a5 32. Rb2 f6 33. c4 Nb6 34. cxd5+ Nxd5 35. g3 Rc7 36. Nc4 a4 37. Na3 Rd7 38. Ke4 Nc3+ 39. Ke3 Nd1+ 40. Kf3 Nxb2 41. Nc2 Rd3+ 42. Ke2 Rxg3 43. h4 Rg4 44. Kd2 Rxh4 45. Kc1 Nd3+ 46. Kd2 Nxf4 47. Kc3 Rh3+ 48. Kb4 a3 49. Nxa3 Rxa3 50. Kxa3 Kd5 51. Kb2 Kd4 52. Kc2 e5 53. Kd2 f5 54. Ke1 e4 55. Kf2 Kd3 56. Ke1 e3 57. Kf1 Kd2 58. Kg1 e2 59. Kh2 e1=Q 1/2-1/2
Game PGN
[Event "rated rapid game"] [Site "https://lichess.org/sppOO2CE"] [Date "2025.01.05"] [Round "-"] [White "anubabbu"] [Black "Maxanam"] [Result "1/2-1/2"] [GameId "sppOO2CE"] [UTCDate "2025.01.05"] [UTCTime "02:49:02"] [WhiteElo "1783"] [BlackElo "1805"] [WhiteRatingDiff "+0"] [BlackRatingDiff "+0"] [Variant "Standard"] [TimeControl "600+0"] [ECO "C11"] [Opening "French Defense: Classical Variation, Steinitz Variation"] [Termination "Normal"] 1. d4 d5 2. e4 e6 3. Nc3 Nf6 4. e5 Nfd7 5. Be3 c5 6. Nce2 cxd4 7. Qxd4 Nc6 8. Qg4 Ndxe5 9. Qg3 g6 10. Nf3 Bg7 11. Ned4 Nxf3+ 12. Nxf3 Bxb2 13. Rb1 Bc3+ 14. Bd2 Bxd2+ 15. Nxd2 Qf6 16. Bb5 Bd7 17. Qd6 Qe5+ 18. Qxe5 Nxe5 19. Bxd7+ Kxd7 20. Rxb7+ Kc6 21. Rb1 Rab8 22. Ke2 Rxb1 23. Rxb1 Ng4 24. h3 Ne5 25. a4 Rc8 26. f4 Nd7 27. Kd3 Nc5+ 28. Kd4 Nxa4 29. Rb4 Nc5 30. Ke5 Nd7+ 31. Kd4 a5 32. Rb2 f6 33. c4 Nb6 34. cxd5+ Nxd5 35. g3 Rc7 36. Nc4 a4 37. Na3 Rd7 38. Ke4 Nc3+ 39. Ke3 Nd1+ 40. Kf3 Nxb2 41. Nc2 Rd3+ 42. Ke2 Rxg3 43. h4 Rg4 44. Kd2 Rxh4 45. Kc1 Nd3+ 46. Kd2 Nxf4 47. Kc3 Rh3+ 48. Kb4 a3 49. Nxa3 Rxa3 50. Kxa3 Kd5 51. Kb2 Kd4 52. Kc2 e5 53. Kd2 f5 54. Ke1 e4 55. Kf2 Kd3 56. Ke1 e3 57. Kf1 Kd2 58. Kg1 e2 59. Kh2 e1=Q 1/2-1/2